Question

Mrs.Mala gives 14 chocolates to her two sons in the ratio 3:4. How many
chocolates does each son get?

Answer 1

Given, chocolates distributed by Mrs.Mala between hee two sons are in the ratio 3 : 4

Let the common multiple be x

Let the part of 1st son be 3x and 2nd son be 4x

Total chocolates = 14


According to the question,

3x + 4x = 14

➾ 7x = 14

➾ x = 2


∴ Chocolates given to 1st son ➾ 3x

➾ 3 × 2

➾ $\green{\boxed{\green{\boxed{\red{\textsf{6}}}}}}$


∴ Chocolates given to 2nd son ➾ 4x

➾ 4 × 2

➾ $\green{\boxed{\green{\boxed{\red{\textsf{8}}}}}}$

Answer 2

Heya !
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Ques → Mrs.Mala gives 14 chocolates to her two sons in the ratio 3:4. How many chocolates does each son get?

Ans. →Total Chocolates = 14

°•° Mrs. Mala divides them in the ratio 3:4

★ Total = 4 + 3 = 7

$= > 1st \: son \: got \: = > \frac{3}{7} \times 14 \\ \\ = > 6 \: chocolates \:$

Similarly ,

$2nd \: son \: got \: = > \frac{4}{7} \times 14 \\ \\ = > 8 \: chocolates$
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★Verification =>

=> 6/8

= 3/4 ✔

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