The length and width of the rectangle are 12 cm and 9 cm. Find its area and perimeter.
Answers
Answer:
Given:-
The length and width of the rectangle are 12 cm and 9 cm. Find its area and perimeter
To Find:
Area and perimeter.
Note:-
●》Area of the rectangle = Length × Breadth.
●》Perimeter of the rectangle = 2 × ( Length + Breadth ).
●》When units are multiplied then they will become unit square. For example- cm × cm = cm².
Solution:-
[ First Area ], Length = 12 cm ; Breadth = 9 cm
☆ According to note first point~
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☆ After doing calculations and accordingly to note third point~
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Area = 108 cm²
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[ Now perimeter ], Length = 12 cm ; Breadth = 9 cm
☆ According to note second point~
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☆ After doing calculations~
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Perimeter = 42 cm
Answer:-
Hence, the area of the rectangle = 108 cm² : Perimeter of the rectangle = 42 cm.
:)
Answer:
The length and width of the rectangle are 12 cm and 9 cm. Find its area and perimeter.
✧GiveN✧:-
In the given rectangle,
Length = 12 cm
Breadth = 9 cm
✧To FinD✧:-
The area and perimetr of the given rectangle.
✧SolutioN✧:-
The length and width of the rectangle is already known , ie,
Length = 12 cm
Breadth =9 cm
As we know,
The formulae applied here are,
⟿ Area of a rectangle = Length × Breadth
⟿ Perimeter of a rectangle = 2(Length + Breadth)
♡Area!♡
12 * 9= 108
♡Perimeter!♡
2(12+8)
2*21
= 42
Happy Learning!☆