Question

the length breadth and height is 8cm, 6cm and 4 cm repetively find the surface area, diagonal and area of four walls ​

Answer 1

Answer:

surface area = 2(lb + bh + lh)

=> 2(8×6+6×4+8×4)

=> 2(48 + 24 + 32) cm2

=> 2 (104)

=> 208 cm2

Lateral surface area = 2h (l+b)

=> 2(8+6)4

=> 112 cm2

Diagonal

$\sqrt{8 {}^{2} + 6 {}^{2} + 4 {}^{2} } = 10.7cm$