Question

The length, breadth and height of a carton is 10m, 8m, and 4m respectively. Find the amount of space occupied by it.​

Answer 1

Answer:

Area of four walls of the room is: 2h(l+b)

A=2h(l+b)=2×3(8+5)=6×13=78 m^2

Area of the ceiling is:

A=l×b=8×5=40 m^2

Total area of the four walls and the ceiling of the room is 78+40=118 m^2

It is given that cost of white washing is Rs.15/m^2 therefore,

Total cost of white washing is:

118×15=1770

Hence, the cost of white washing the walls is Rs.1770.

Answer 2

$Lateral \: Surface \: Area \\ = 2h \: (l+b)$

$= 2(4)(10 + 8)$

$= 8(18)$

$= 8 \times 18$

$= 144 \: {m}^{2}$