the length breadth and height of a cuboid are 4m 3m and 2m respectively then surface area of cuboid will be
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Answered by
9
Hey friend..!!! here's your answer
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Length ==> 4m
Breadth => 3m
Height ==> 2m
Surface area of cuboid ==> 2(lb + bh + hl)
= 2(4×3 + 3×2 + 2×4) m^2
= 2(12 + 6 +8) m^2
= 2(26) m^2
= 52 m^2
So that the surface area of cuboid is 52 m^2
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#Hope its help you dear#
☺
_________________________
Length ==> 4m
Breadth => 3m
Height ==> 2m
Surface area of cuboid ==> 2(lb + bh + hl)
= 2(4×3 + 3×2 + 2×4) m^2
= 2(12 + 6 +8) m^2
= 2(26) m^2
= 52 m^2
So that the surface area of cuboid is 52 m^2
___________________
#Hope its help you dear#
☺
Answered by
5
Given,
l = 4m
b = 3m
h = 2m
Lateral surface area of Cuboid = 2 (bh + hl)
= 2 [ (3×2) + (2×4) ]
= 2 ( 6 + 8)
= 2 (14)
= 28 m^2
Total surface area of cuboid = 2 ( lb + bh + hl)
= 2 [ (4×3) + (3×2) + (2×4) ]
= 2 [ 12 + 6 + 8]
= 2 [26]
= 52 m^2
Hope it helps.
l = 4m
b = 3m
h = 2m
Lateral surface area of Cuboid = 2 (bh + hl)
= 2 [ (3×2) + (2×4) ]
= 2 ( 6 + 8)
= 2 (14)
= 28 m^2
Total surface area of cuboid = 2 ( lb + bh + hl)
= 2 [ (4×3) + (3×2) + (2×4) ]
= 2 [ 12 + 6 + 8]
= 2 [26]
= 52 m^2
Hope it helps.
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