Question

water drops fall at regular interval from a tap which is 5m above the ground .the thirtd drop is leaving the tap at the instant the first drop touches the ground .how far above the ground is the second drop

Answer 1

the second drop is 3.75m above the ground when 1st drop touches the ground

given,
s=5m,a=g=10m/s^2
first,calculate the time taken for the first drop to reach the ground
s=ut+at^2/2
the drop was initiallty at rest
5=10t^2/2 (s=5m,g=10m/s^2)
t^2=1
t=±1
t=1 (since, time can't be negitive)
time taken for the 1st drop after leaving the tap is 1sec ,
time taken for the 2nd drop after leaving the tap is 0.5s (t=1/2=0.5)
s=10(0.5)^2/2 (s=ut+at^2/2)
s=10(0.25)/2
s=2.5/2
s=1.25m
this is the distance from tap to drop.so, the distance from ground to drop is
h=5−1.25
h=3.75 m

Answer 2

Second drop should be 3.75 m above the ground..