Math, asked by jashanjanjua7, 4 months ago

The length , breadth and height of a cuboid are in the ratio 3:2:1. If its volume is 162
cm³ , find its total surface area.



please answer these question fast tomorrow is my exam​

Answers

Answered by adarshpratapsingh367
1

Answer:

correct answer is 198cm^2

Answered by Anonymous
60

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The length , breadth and height of a cuboid are in the ratio 3:2:1. If its volume is 162

cm³ , find its total surface area.

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T.S.A of Cuboid is 198cm³

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  • Ratio of dimensions of cuboid is 3:2:1
  • Volume of Cuboid = 162 cm³

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  • T.S.A of Cuboid = ?

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 \bf Volume \:  of \:  Cuboid =l \times b \times h

 \bf T.S.A  \: of  \: Cuboid  = 2(lb \times bh \times hl)

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Let, the length be 3x, breadth be 2x and height be x.

 \bf Volume \:  of  \: Cuboid =162 {cm}^{2}

 \bf \implies l \times b \times h = 162

 \bf \implies 3x \times 2x \times x = 162

 \bf \implies  {6x}^{3}  = 162

 \bf \implies  {x}^{3}  = 162 \div 6

 \bf \implies  {x}^{3}  = 27

 \bf \implies x  = \sqrt[3]{27}

 \bf \implies x = 3cm

 \bf T.S.A  \: of  \: Cuboid  = 2(lb \times bh \times hl)

 \bf  = 2(9 \times 6 + 6 \times 3 + 3 \times 9)

 \bf  = 2(54 + 18 + 27)

 \bf  = 2 \times 99

 \bf  = 198 {cm}^{3}

Therefore, T.S.A of Cuboid is 198cm³.

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