The length, breadth, and height of a cuboid are in the ratio 5:3:2, and its total surface area is 3,968 cm².
Find the dimensions of the cuboid.
The area of four walls of a room is 90 m². If the room is 7 m long and 2 m wide, then find the height of the room.
Answers
Answer:
Let common ratio be x
length=5x
breadth=3x
height=2x
Tsa=2(lb+bh+hl)
3968=2* (15xsquare + 6xsquare +10xsquare)
3968=2*31xsquare
3968=62xsquare
3968/62=x square
√64=x
8=x
Length=40
Breadth=24
Height=16
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Step-by-step explanation:
q2.
Length=7
Breadth=2
Csa=2*(l+b)h
90= 18h
90/18=h
5=h
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Step-by-step explanation:
let the length =5x
" " breath = 3x
" " height = 2x
Total surface area = 3,968cm^2
Total surface area = 2(lb+bh+hl)
3968 = 2(15x^2 + 6x^2 + 10x^2)
3968 = 2(31x^2)
3968 = 62x^2
3968/62 = x^2
64 = x^2
8 = x
length = 5*8 = 40cm
breadth = 3*8 = 24cm
height = 2*8 = 16cm
Area of four walls = 90 m^2
length = 7m
breadth = 2m
height = ?
Area of four walls = 2(l+b)h
90 = 2(7+2)h
90 = 2*9*h
90 = 18h
90/18 = h
5m = height