Question

The length, breadth, and height of a cuboid are in the ratio 5:3:2, and its total surface area is 3,968 cm².
Find the dimensions of the cuboid.
The area of four walls of a room is 90 m². If the room is 7 m long and 2 m wide, then find the height of the room.​

Answer 1

Answer:

Let common ratio be x

length=5x

breadth=3x

height=2x

Tsa=2(lb+bh+hl)

3968=2* (15xsquare + 6xsquare +10xsquare)

3968=2*31xsquare

3968=62xsquare

3968/62=x square

√64=x

8=x

Length=40

Breadth=24

Height=16

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Step-by-step explanation:

q2.

Length=7

Breadth=2

Csa=2*(l+b)h

90= 18h

90/18=h

5=h

Brainliest Mark kar dena

Thanks wagera bhi dena khoob saare dusre question pe bhi

Answer 2

Step-by-step explanation:

let the length =5x

" " breath = 3x

" " height = 2x

Total surface area = 3,968cm^2

Total surface area = 2(lb+bh+hl)

3968 = 2(15x^2 + 6x^2 + 10x^2)

3968 = 2(31x^2)

3968 = 62x^2

3968/62 = x^2

64 = x^2

8 = x

length = 5*8 = 40cm

breadth = 3*8 = 24cm

height = 2*8 = 16cm

Area of four walls = 90 m^2

length = 7m

breadth = 2m

height = ?

Area of four walls = 2(l+b)h

90 = 2(7+2)h

90 = 2*9*h

90 = 18h

90/18 = h

5m = height