Math, asked by Vishalkohli1100, 1 year ago

The length, breadth, and height of a cuboidal water tank are 7m,6m,and 15m, respectively. If 8400litres of water is pumped out of the water tank,find the fall in the water level in the water tank.​

Answers

Answered by Antihero10SK
2

Volume of cuboidal tank=l*b*h

=700*600*1500

=630,000,000cm^3

We know that 1000cm^3=1 litre

so amount of water left=630000-8400

=621,600litres

Answered by nilesh102
2

\textbf{\huge\underline{\underline\red{solution} : -  }} \\  \\ \bold{\underline\purple{here \: we \: know}} \\  \\  \red{1.} \bold \blue{ \: length  \: (l)\: of \: cuboidal \:water \: tank \: is \: 7 \: m .} \\ \red{2.} \bold \blue{ \: breadth  \:( b)\: of \: cuboidal \:  water\: tank \: is \: 6 \: m.} \\ \red{3.} \bold \blue{ \: height  \: (h)\: of \: cuboidal \: water  \: tank \: is \: 15 \: m.} \\  \red{4.} \bold \blue{  \: 8400 \: litres \: of \: water \: pumped \: out \: from } \\ \:  \:  \:  \: \bold \blue{water \: tank.} \\  \\  \underline\bold\red{ \: To \: find \:  \: fall \: of \: water \: level \: in \: water \: tank.}  \\  \\ \underline\bold\red{  \: we \: use \: formula : -  } \\  \\  =  &gt; \underline\bold\purple{volume \: of \: cuboid } = \bold\red{l \times  b\times  h} \\  \\ =  &gt; \underline\bold\purple{volume \: of \: cuboid } = \bold\red{7 \times  6\times  15} \\  \\ =  &gt; \underline\bold\purple{volume \: of \: cuboid } = \bold\red{630 \:  {m}^{3} } \\  \\  \underline\bold\red{ \: we \: know \: }  \:  \:   \fbox\bold\pink{ \: 1 \:  {m}^{3}  =  \: 1000 \: litre \: } \\  \\  \underline\bold\blue{ \: hence} \\ \\  \bold\purple{\:630 \:  {m}^{3}   = 630 \times 1000 = 630000 \: litre} \\  \\ \underline \bold\blue{now} \\  \\  \underline\bold\purple{fall \: of \: water \: level \: in \: water \: tank}  \\ = \:  \:  \: \bold\blue{(water \: in \: water \: tank \:) } \\  \:  \:  \:   -  \bold\orange{ \: (\: 8400 \: litre water \: pumped \: out)} \\  \\ \bold\purple{fall \: of \: water \: level... =( 630000 \:  - 8400 \:) litre} \\  \\ \bold\purple{fall \: of \: water \: level...  = 621600 \: litre} \\  \\ </p><p> \underline \bold \red{Hence  \blue{\: 621600 \: litre \: }water \: remain \: in \:water  \:}  \\ \underline \bold \red{ tank \: after\blue { \: 8400 \: litre \: } \: of \: water  \: pumped \: out.}

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