The length, breadth and height of a room are 5 m, 4 m and 3 m respectively. Find
the cost of white washing the walls of the room and the ceiling at the rate
7.50 m
Answers
Answer:
Step-by-step explanation:
1.Area of four walls of a rom=2(l+b)×h
=2(5+4)×3
=2×9×3
=54m^2
2. Area of the ceiling =2(l+b)
=2(5+4)
=18m^2
3. Total area=54+18=72m^2
4. Cost of white washing the walls and ceiling at the rate of 7.50 per m=
7.50×72= RS 540.
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Answer:
555 rupees
Step-by-step explanation:
Given--->
---------
Length =5m ,Breadth=4m ,height=3m
Cost of whitewashing = 7.50 / m²
To find--->
------------
Cost of whitewashing four walls and ceiling
Solution--->
--------------
Area of four walls=2( l + b ) h
=2( 5 + 4 )× 3
=2( 9 )× 3
=54 cm²
Area of ceiling = l × b
=5 × 4
=20 cm²
Area of four walls and ceiling = 54 + 20
= 74 cm²
Cost of whitewashing =7.50 /m²
Total cost of whitewashing four walls and ceiling = 74 × 7.50
= 555 rupees
1)Volume of cuboid=l b h
2)T S A of cuboid =2(lb +bh +lh)
3)Volume of cube=side³