Question

The length, breadth and height of a room are 5 m, 4 m and 3 m respectively. Find the cost of white washing the walls of the room and ceiling at the rate of Rs 7.50 per m2.

Answer 1

$\large{\underline{\underline{\textsf{\maltese\:{\green{Given}}}}}}$

$\sf{Length \:(l)\: of \:room = 5m}$

$\sf{Breadth\: (b)\: of\: room = 4m}$

$\sf{Height\: (h) \:of\: room = 3m}$

$\sf{Cost\: of\: white \:wash \:per \: m^2\: area\: is\: ₹\:7.50 }$

$\large{\underline{\underline{\textsf{\maltese\:{\green{To\:Find}}}}}}$

$\sf{The\: cost\: of \: white \: washing \: the \: walls \: of \: the\: room}$ $\sf{and\: ceiling \: at\: the\: rate\: of\: ₹\: 7.50 \: per\: m^2}$

$\large{\underline{\underline{\textsf{\maltese\:{\green{Solution}}}}}}$

$\sf\color{navy}{It \:can\: be\: observed\: that \:four\: walls\: and\: the\: ceiling}$ $\sf\color{navy}{of\: the\: room\: are\: to\: be\: white \:washed.}$

$\sf{Total\: area\: to \:be \:white\: washed = Area\: of \:walls + Area\: of \:ceiling\: of \:room}$

$\sf{= 2lh+2bh+lb}$

$\sf{= [2×5×3+2×4×3+5×4]}$

$\sf{= (30+24+20)}$

$\sf{= 74}$

$\sf{Area = 74 m^2}$

Also,

$\sf{Cost\: of\: white \:wash \:per\: m^2\: area\: = ₹\:7.50 }$

$\sf{Cost \:of\: white\: washing\: 74\: m^2 \:area = ₹ \:(74×7.50)}$

$\sf{= ₹\: 555}$

Answer 2

Step-by-step explanation:

• $\large{\underline{\underline{\textsf{\maltese\:{\red{Given}}}}}}$

$\sf{Length \:(l)\: of \:room = 5m}$

$\sf{Breadth\: (b)\: of\: room = 4m}$

$\sf{Height\: (h) \:of\: room = 3m}$

$\sf{Cost\: of\: white \:wash \:per \: m^2\: area\: is\: ₹\:7.50 }$

• $\large{\underline{\underline{\textsf{\maltese\:{\red{To\:Find}}}}}}$
• $\sf{The\: cost\: of \: white \: washing \: the \: walls \: of \: the\: room}$ $\sf{and\: ceiling \: at\: the\: rate\: of\: ₹\: 7.50 \: per\: m^2}$

• $\large{\underline{\underline{\textsf{\maltese\:{\orange{Solution}}}}}}$

$\sf\color{lime}{It \:can\: be\: observed\: that \:four\: walls\: and\: the\: ceiling}$ $\sf\color{lime}{of\: the\: room\: are\: to\: be\: white \:washed.}$

$\sf{Total\: area\: to \:be \:white\: washed = Area\: of \:walls + Area\: of \:ceiling\: of \:room}$

$\sf{= 2lh+2bh+lb}$

$\sf{= [2×5×3+2×4×3+5×4]}$

$\sf{= (30+24+20)}$

$\sf{= 74}$

$\sf{Area = 74 m^2}$

Also,

$\sf{Cost\: of\: white \:wash \:per\: m^2\: area\: = ₹\:7.50 }$

$\sf{Cost \:of\: white\: washing\: 74\: m^2 \:area = ₹ \:(74×7.50)}$

$\sf{= ₹\: 555}$