The length, breadth and height of a room are 6 m, 5 m and 4 m respectively. (a) Find the Total surface area of
the room (b) Find the cost of whitewashing the walls of the room and the ceiling at the rate of ₹ 5 per m2
.
Answers
Answer:
The required cost is ₹370✌️
Step-by-step explanation:
Total surface area of the room =6×5+6×4+5×4 m²
=30+24+20 m²
=74m²
Now cost of white washing for 1 m² =₹5
Therefore cost of white washing 74 m²=₹ 74×5
=₹370
Answer:
Area to be whitewashed = area of four walls + area of ceiling
Formulas to be noted :−
Area of four walls =2 ( length + breadth ) × height
Area of ceiling = area of rectangle = length × breadth
In the question, length of the room =6m
breadth of the room =4.5m
height of the room =3m
On the basis of formulas given above :−
Area of four walls =2(6m+4.5m)x3m
Area of four walls =2(10.5m)x3m
Area of four walls =21mx3m
Area of four walls =63m
2
Area of ceiling =6m×4.5m
Area of ceiling =27m
2
Therefore, area to be whitewashed =63m
2
+27m
2
Area to be whitewashed =90m
2
Cost of whitewashing = rate at which area is being whitewashed × area to be whitewashed
Cost of whitewashing =Rs8/m
2
×90m
2
Cost of whitewashing =Rs8×90
Cost of whitewashing =Rs.720.