Question

The length, breadth and
height of a room are 8. 25 m,
6.75 m and 4.50 m respectively
Determine the longest tape
which can measure the three
dimensions of the room excatly.​

Answer 1

Answer:

Step-by-step explanation:

Let us factorise all three given dimensions.

8.25 = 0.3×0.5×5×11

675=0.3×3×3×0.5×5

450=2×0.3×3×0.5×5

Hence, 3, 5 and 5 are the common prime factors here.

So, H.C.F =0.3×0.5×5=0.75

Therefore, we need 0.75 cm longest tape to measure the three dimensions of the room.

HOPE THIS HELPS YOU

pls mark brainliest

Answer 2

$➪ \sf \red{Answer:-}$

$\huge{ ➫} \tt GIVEN:-$

$length \: of \: room \: = 7m25cm = 725cm \\ breadth \: of \: room \: = 9m25cm = 925cm \\ height \: of \: room \: = 8m25cm = 825cm$

$\huge ➫ \sf FIND:-$

$now \: we \: find \: HCF \: of \: 725,925 \: and \: 825$

${\huge ➫ {\mathfrak{Solution:-}}}$

$725 = 5 \times 5 \times29 \\ 925 = 5 \times 5 \times 37 \\ 825 = 3 \times 5 \times 5 \times 11 \\ \\ so, \: heighest \: common \: factor \: is \: 5 \times 5 = 25 \\ therefore \: HCF \: of \: 725,925,825 \: is \: 25. \\ \therefore 25m is \: the \: longest \: tape \: measure \: which \: can \: measure \: all \: the \: dimensions.$

$so, \: answer \: is \: \boxed{ \mathfrak{ 25m}}$