Question

the Length breadth and height of a room are 825 CM 675 cm and 4 m 50 cm respectively determine the largest tape which can measure the three dimensions of the room​

Answer 1

find the h.c.f of 825,675,450

....to get the largest tape to measure the three dimensional of the room

......Ans. =75cm

Answer 2

$➪ \sf \red{Answer:-}$

$\huge{ ➫} \tt GIVEN:-$

$length \: of \: room \: = 7m25cm = 725cm \\ breadth \: of \: room \: = 9m25cm = 925cm \\ height \: of \: room \: = 8m25cm = 825cm$

$\huge ➫ \sf FIND:-$

$now \: we \: find \: HCF \: of \: 725,925 \: and \: 825$

${\huge ➫ {\mathfrak{Solution:-}}}$

$725 = 5 \times 5 \times29 \\ 925 = 5 \times 5 \times 37 \\ 825 = 3 \times 5 \times 5 \times 11 \\ \\ so, \: heighest \: common \: factor \: is \: 5 \times 5 = 25 \\ therefore \: HCF \: of \: 725,925,825 \: is \: 25. \\ \therefore 25m is \: the \: longest \: tape \: measure \: which \: can \: measure \: all \: the \: dimensions.$

$so, \: answer \: is \: \boxed{ \mathfrak{ 25m}}$