Social Sciences, asked by sonalvagh16, 10 months ago

The length, breadth and height of a room are 825 cm, 675 cm and 450 cm respectively. Find the longest tape which can measure the three dimensions of the room exactly.?
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Answers

Answered by singlesitaarat31
24

 \huge \red {\underline {HAYE\:MATE}}

\huge  \purple   {\boxed {\boxed {\mathbb {Answer}}}}

 \huge \red {\underline {Given :- }}

Length = 8 m 50 cm = 850 cm  

Breadth = 6 m 75 cm = 675 cm  

Height = 4 m 50 cm = 450 cm

 \huge \pink {\underline {To\: Find  :- }}

Length of the longest rod.

 \huge \green {\underline {Formula \:to\: be \:used  :- }}

HCF of given dimensions

\huge  \blue   {\boxed {\boxed {\mathbb {solution:-  }}}}

we have to find the HCF of 825, 675 and 450 .

825 = 5 × 5 × 3 × 11

675 = 5 × 5 × 3 × 3 × 3

450 = 2 × 3 × 3 × 5 × 5

HCF = 5 × 5 × 3

HCF = 75 cm.

Hence, the length of the longest rod which can measure the three dimensions of the room exactly is 75 cm.

 \huge \blue {\mathbb {THANKS}}

 \huge \green {FOllOW\:ME}

 \huge \purple {\mathbb {SINGLE\:STAR}}

Answered by Anonymous
1

\huge  \purple   {\boxed {\boxed {\mathbb {Answer}}}}

 \huge \red {\underline {Given :- }}

Length = 8 m 50 cm = 850 cm  

Breadth = 6 m 75 cm = 675 cm  

Height = 4 m 50 cm = 450 cm

 \huge \pink {\underline {To\: Find  :- }}

Length of the longest rod.

 \huge \green {\underline {Formula \:to\: be \:used  :- }}

HCF of given dimensions

\huge  \blue   {\boxed {\boxed {\mathbb {solution:-  }}}}

we have to find the HCF of 825, 675 and 450 .

825 = 5 × 5 × 3 × 11

675 = 5 × 5 × 3 × 3 × 3

450 = 2 × 3 × 3 × 5 × 5

HCF = 5 × 5 × 3

HCF = 75 cm.

Hence, the length of the longest rod which can measure the three dimensions of the room exactly is 75 cm.

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