the Length breadth and height of a room is 5 M 4 m and 3 M respectively find the cost of the white washing the wall of the room and ceiling at the rate of rupees 7.50 per metre square
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Answered by
3
here Total surface area of the room =>
2(lb+bh+hl)
=> 2(5*4+4*3+3*5)
=>2(20+12+15)=>2*47=>94m2
rate => 7.5/m2
therefore cost => 94*7.5=> rs.705
2(lb+bh+hl)
=> 2(5*4+4*3+3*5)
=>2(20+12+15)=>2*47=>94m2
rate => 7.5/m2
therefore cost => 94*7.5=> rs.705
Answered by
6
l= 5m
b= 4m
h= 3m
we need the surface area for white washing
so, surface area of walls + surface area of the ceiling
that is, LSA + (lb)
LSA of a cuboid = 2h(l+b)
= 2(3)(5+4)
=6(9)
= 54 m^2
surface area of the ceiling -
5*4= 20 m^2
total surface area to be white washed= 74 m^2
total cost = 74*7.5=555 rupees
b= 4m
h= 3m
we need the surface area for white washing
so, surface area of walls + surface area of the ceiling
that is, LSA + (lb)
LSA of a cuboid = 2h(l+b)
= 2(3)(5+4)
=6(9)
= 54 m^2
surface area of the ceiling -
5*4= 20 m^2
total surface area to be white washed= 74 m^2
total cost = 74*7.5=555 rupees
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