Question

The length, breadth and height of closed wooden box are 90 cm, 50 cm and 30 cm respectively. Find the outer surface area of the box.

Answer 1

surface area of cuboid =
2(lb+bh+lh)
2(8700)cm^2
17400cm^2

Answer 2

total surface area =2(lb+bh+hl)
=2(90×50+50×30+30×90)
=2(450+150+270)
=2(870)
=1740