Question

) The length, breadth and thickness of
a rectangular sheet of metal are 4.234
m, 1.005 m, and 2.01 cm respectively.
Give the area and volume of the sheet to
correct significant figures.
[Ans: 4.255, 8.56*10')​

Answer 1

Explanation:

A=2×(L×B+B×T+T×L)

∴A=2×(4.234×1.005+1.005×0.0201+0.0201×4.234)

∴A=2×(4.2552+0.0202+0.0851)

∴A=8.721m

2

∴A=8.721m

2

to correct significant digits

V=L×B×T

∴V=4.234×1.005×0.0201

∴V=0.0855m

3

to correct significanA=2×(L×B+B×T+T×L)

∴A=2×(4.234×1.005+1.005×0.0201+0.0201×4.234)

∴A=2×(4.2552+0.0202+0.0851)

∴A=8.721m

2

∴A=8.721m

2

to correct significant digits

V=L×B×T

∴V=4.234×1.005×0.0201

∴V=0.0855m

3

to correct significant digits

Answer 2

Answer:

A=2×(L×B+B×T+T×L)

∴A=2×(4.234×1.005+1.005×0.0201+0.0201×4.234)

∴A=2×(4.2552+0.0202+0.0851)

∴A=8.721m2

∴A=8.721m2  to correct significant digits

V=L×B×T

∴V=4.234×1.005×0.0201

∴V=0.0855m3 to correct significant digits