The length, breadth and thickness of a rectangular sheet of metal are 3.234 m, 2.005 m, and 1.01 cm respectively. Give the area and volume of the sheet to correct significant figures.
Answers
Answer:
A=2×(L×B+B×T+T×L)
∴A=2×(4.234×1.005+1.005×0.0201+0.0201×4.234)
∴A=2×(4.2552+0.0202+0.0851)
∴A=8.721m2
∴A=8.721m2 to correct significant digits
V=L×B×T
∴V=4.234×1.005×0.0201
∴V=0.0855m3 to correct significant digits
Given : The length, breadth and thickness of a rectangular sheet of metal are 3.234 m, 2.005 m, and 1.01 cm respectively.
To Find : the area and volume of the sheet to correct significant figures.
Solution:
Length L = 3.234 m
Breadth B = 2.005 m
Thickness T = 1.01 cm = 0.0101 m
Area = 2 ( LB + BT + LT)
= 2( 3.234 * 2.005 + 2.005* 0.0101 + 3.234* 0.0101)
=13.07417 m²
Volume - LBT
= 3.234 * 2.005 * 0.0101
= 0.06549 m³
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