Physics, asked by PragyaTbia, 1 year ago

The length, breadth and thickness of a rectangular sheet of metal are 4.234 m, 1.005 m and 2.01 cm respectively. Give the area and volume of the sheet to correct significant figures.

Answers

Answered by gadakhsanket
484
Hii dear,

# Answer- A=8.72 m^2 and V=0.0855 m^3.

# Given-
l = 4.234 m ...(4 significant figures)
b = 1.005 m ...(4 significant figures)
h = 2.01 cm = 0.0201 m ...(3 significant figures)

# Solution-
Area and volume both must have least significant figures i.e. 3.

Surface area of the sheet
= 2 (l×b + b×h + h×l)
= 2 (4.234×1.005 + 1.005×0.0201 + 0.0201×4.234)
= 2 (4.25517 + 0.02620 + 0.08510)
= 2×4.360
= 8.7209478
= 8.72 m^2 (3 significant figures)

Volume of the sheet
= l×b×h
= 4.234×1.005×0.0201
= 0.085528917
= 0.0855 m^3 (3 significant figures)

Hence, our answer is A=8.72 m^2 and V=0.0855 m^3.
Answered by Anonymous
144

==============ⓢⓦⓘⓖⓨ

\huge\mathfrak\red{hello...frd\:swigy\:here}

==============ⓢⓦⓘⓖⓨ

Length of sheet, l = 4.234 m Breadth of sheet, b = 1.005 m Thickness of sheet, h = 2.01 cm = 0.0201 m

The given table lists the respective significant figures:

QUANTITY. 1) l. 2)b. 3) h

NUMBER. 1)4.234 2)1.005 3)2.01

SIGNIFICANT FIG. 1). 4 2). 4 3). 3

Hence, area and volume both must have least significant figures i.e., 3.

Surface area of the sheet

= 2 (l × b + b × h + h × l)

= 2(4.234 × 1.005 + 1.005 × 0.0201 + 0.0201 × 4.234)

= 2 (4.25517 + 0.02620 + 0.08510)

= 2 × 4.360 = 8.72 m2

Volume of the sheet

= l × b × h = 4.234 × 1.005 × 0.0201

= 0.0855 m3

This number has only 3 significant figures i.e., 8, 5, and 5.

I hope, this will help you

=======================

<marquee behaviour-move bigcolour-pink><h1>☺ThankYou✌</h1></marquee>

·.¸¸.·♩♪♫ ⓢⓦⓘⓖⓨ ♫♪♩·.¸¸.·

___________♦♦⭐♦ ♦___________

Similar questions