The length, breadth and thickness of a rectangular sheet of metal are 4.234 m, 1.005 m and 2.01 cm respectively. Give the area and volume of the sheet to correct significant figures.
Answers
# Answer- A=8.72 m^2 and V=0.0855 m^3.
# Given-
l = 4.234 m ...(4 significant figures)
b = 1.005 m ...(4 significant figures)
h = 2.01 cm = 0.0201 m ...(3 significant figures)
# Solution-
Area and volume both must have least significant figures i.e. 3.
Surface area of the sheet
= 2 (l×b + b×h + h×l)
= 2 (4.234×1.005 + 1.005×0.0201 + 0.0201×4.234)
= 2 (4.25517 + 0.02620 + 0.08510)
= 2×4.360
= 8.7209478
= 8.72 m^2 (3 significant figures)
Volume of the sheet
= l×b×h
= 4.234×1.005×0.0201
= 0.085528917
= 0.0855 m^3 (3 significant figures)
Hence, our answer is A=8.72 m^2 and V=0.0855 m^3.
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Length of sheet, l = 4.234 m Breadth of sheet, b = 1.005 m Thickness of sheet, h = 2.01 cm = 0.0201 m
The given table lists the respective significant figures:
QUANTITY. 1) l. 2)b. 3) h
NUMBER. 1)4.234 2)1.005 3)2.01
SIGNIFICANT FIG. 1). 4 2). 4 3). 3
Hence, area and volume both must have least significant figures i.e., 3.
Surface area of the sheet
= 2 (l × b + b × h + h × l)
= 2(4.234 × 1.005 + 1.005 × 0.0201 + 0.0201 × 4.234)
= 2 (4.25517 + 0.02620 + 0.08510)
= 2 × 4.360 = 8.72 m2
Volume of the sheet
= l × b × h = 4.234 × 1.005 × 0.0201
= 0.0855 m3
This number has only 3 significant figures i.e., 8, 5, and 5.
I hope, this will help you
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