the length, breadth and thickness of a strip are (10.0 +- 0.1)cm, (1.00+-0.01)cm and (0.100+-0.001)cm respectively. the most probable error in it's volume is?
Answers
Answered by
73
Length , L = (10 ± 0.1) cm
Breadth , B = (1 + 0.01) cm
Thickness , H = (0.1 ± 0.001) cm
We know, volume of cuboid = length × Breadth × thicness
e.g., V = L × B × H
so, for finding error in V
Use , ∆V/V = ∆L/L + ∆B/B + ∆H/H
First find V = L × B × H
= 10 × 1 × 0.1 = 1 cm³
Now, ∆V/1 = 0.1/10 + 0.01/1 + 0.001/0.1
= 0.01 + 0.01 + 0.01 = 0.03
Hence, volume of cuboid = (1 ± 0.03) cm³
Breadth , B = (1 + 0.01) cm
Thickness , H = (0.1 ± 0.001) cm
We know, volume of cuboid = length × Breadth × thicness
e.g., V = L × B × H
so, for finding error in V
Use , ∆V/V = ∆L/L + ∆B/B + ∆H/H
First find V = L × B × H
= 10 × 1 × 0.1 = 1 cm³
Now, ∆V/1 = 0.1/10 + 0.01/1 + 0.001/0.1
= 0.01 + 0.01 + 0.01 = 0.03
Hence, volume of cuboid = (1 ± 0.03) cm³
Answered by
27
Solution:-
given by:-
》Length( l) = (10 ± 0.1) cm
》Breadth (b )= (1 + 0.01) cm
》Thickness ( h) = (0.1 ± 0.001) cm
》volume of cuboid = length × Breadth × thicness
》 V = l× b× h
》error in Volume
》∆V/V = ∆l/l+ ∆b/b + ∆h/h
》First find V = l × b× h
》= 10 × 1 × 0.1 = 1 cm^3
》Now, ∆V/1 = 0.1/10 + 0.01/1 + 0.001/0.1
》= 0.01 + 0.01 + 0.01 = 0.03
Hence, volume of cuboid = (1 ± 0.03) cm^3
■I HOPE ITS HELP■
given by:-
》Length( l) = (10 ± 0.1) cm
》Breadth (b )= (1 + 0.01) cm
》Thickness ( h) = (0.1 ± 0.001) cm
》volume of cuboid = length × Breadth × thicness
》 V = l× b× h
》error in Volume
》∆V/V = ∆l/l+ ∆b/b + ∆h/h
》First find V = l × b× h
》= 10 × 1 × 0.1 = 1 cm^3
》Now, ∆V/1 = 0.1/10 + 0.01/1 + 0.001/0.1
》= 0.01 + 0.01 + 0.01 = 0.03
Hence, volume of cuboid = (1 ± 0.03) cm^3
■I HOPE ITS HELP■
Similar questions