Math, asked by mathsteacher, 1 year ago

the length bredth and height of a cuboidal water tank are 7m,6m,and 15m, respectively.if 8400 litres of water is pumped out of the water tank ,find the fall in the water level in the water tank

Answers

Answered by MANKOTIA
0
water level in water tank= 63m^3=63×1000litre/8400litre
=630/84
=90/12
=15/2
7.5

mathsteacher: answer is 20 dear
Answered by nilesh102
2

\textbf{\huge\underline{\underline\red{solution} : -  }} \\  \\ \bold{\underline\purple{here \: we \: know}} \\  \\  \red{1.} \bold \blue{ \: length  \: (l)\: of \: cuboidal \:water \: tank \: is \: 7 \: m .} \\ \red{2.} \bold \blue{ \: breadth  \:( b)\: of \: cuboidal \:  water\: tank \: is \: 6 \: m.} \\ \red{3.} \bold \blue{ \: height  \: (h)\: of \: cuboidal \: water  \: tank \: is \: 15 \: m.} \\  \red{4.} \bold \blue{  \: 8400 \: litres \: of \: water \: pumped \: out \: from } \\ \:  \:  \:  \: \bold \blue{water \: tank.} \\  \\  \underline\bold\red{ \: To \: find \:  \: fall \: of \: water \: level \: in \: water \: tank.}  \\  \\ \underline\bold\red{  \: we \: use \: formula : -  } \\  \\  =  &gt; \underline\bold\purple{volume \: of \: cuboid } = \bold\red{l \times  b\times  h} \\  \\ =  &gt; \underline\bold\purple{volume \: of \: cuboid } = \bold\red{7 \times  6\times  15} \\  \\ =  &gt; \underline\bold\purple{volume \: of \: cuboid } = \bold\red{630 \:  {m}^{3} } \\  \\  \underline\bold\red{ \: we \: know \: }  \:  \:   \fbox\bold\pink{ \: 1 \:  {m}^{3}  =  \: 1000 \: litre \: } \\  \\  \underline\bold\blue{ \: hence} \\ \\  \bold\purple{\:630 \:  {m}^{3}   = 630 \times 1000 = 630000 \: litre} \\  \\ \underline \bold\blue{now} \\  \\  \underline\bold\purple{fall \: of \: water \: level \: in \: water \: tank}  \\ = \:  \:  \: \bold\blue{(water \: in \: water \: tank \:) } \\  \:  \:  \:   -  \bold\orange{ \: (\: 8400 \: litre water \: pumped \: out)} \\  \\ \bold\purple{fall \: of \: water \: level... =( 630000 \:  - 8400 \:) litre} \\  \\ \bold\purple{fall \: of \: water \: level...  = 621600 \: litre} \\  \\ </p><p> \underline \bold \red{Hence  \blue{\: 621600 \: litre \: }water \: remain \: in \:water  \:}  \\ \underline \bold \red{ tank \: after\blue { \: 8400 \: litre \: } \: of \: water  \: pumped \: out.}

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