The length (in metres) of the longest rod that can beput in a room of dimensions 10 m x 10m x 5m is
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Longest rod that can be put in that room will definately be the diagonal of room. So we will find the length of diagonal therefore we need length and breadth these are l*b=10*10 Now the surface of room ha
s rectangular shape we draw its diagonal and in this right triangle b²+p²=h². Here hypotanuose is diagonal. So 10²+10²=h². 100+100=h². 200=h². H=14.3cm. Thanks. May it help you
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