Question

The length of a chord AB of a circle with radius 10cm is 16 cm, if OD perpendicular to AB, then find the length of

OD ( O is the centre).​

Answer 1

Step-by-step explanation:

Consider AB as the chord with O as the centre and radius 10cm So we get OA = 10 cm and AB = 16cm Construct OL ⊥ AB Perpendicular from the centre of a circle to a chord bisects the chord So we get AL = ½ × AB By substituting the values AL = ½ × 16 So we get AL = 8 cm Consider △ OLA Using the Pythagoras theorem it can be written as OA2 = OL2 + AL2 By substituting the values we get 102 = OL2 + 82 On further calculation OL2 = 102 – 82 So we get OL2 = 100 – 64 By subtraction OL2 = 36 By taking the square root OL = √36 So we get OL = 6cm Therefore, the distance of the chord from the centre of the circle is 6cm.Read more on Sarthaks.com - https://www.sarthaks.com/727412/chord-length-16cm-drawn-circle-radius-10cm-find-the-distance-the-chord-from-centre-circle

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Answer 2

Answer:

chord of length 16 cm is drawn in a circle of radius 10 cm. Find the distance of the chord from the centre of the circle.

Step-by-step explanation:

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