Question

The length of a conducting wire is 0,5mm,If it's reactance is 30 ohm, what is resistivity of its material?

Answer 1

Heya...

___________________________________________________________

ANSWER FOR YOUR QUESTION IS HERE:

:::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::

R = 30 ohm

l = 50cm = 0.5m

r = 0.5mm = 5×10^(-4)m

\rho =?

R= \rho \frac{l}{A} \\ \\ \rho = \frac{RA}{l}= \frac{30 \times \pi \times (5\times 10^{-4})^2}{0.5}\\ \\ \rho=4.7 \times 10^{-5}\ ohm\ meter

___________________________________________________________

Hope it helps

(ᵔᴥᵔ)

Plzz Mark it as BRAINLIEST

Answer 2

Given :

Length = 50 cm or 0.5 m .

Resistance = 30 Ω

Radius = 0.5 mm or 0.5 × 10⁻³ m

To find: We have to find the resistivity of material in the given question.

We would first find the area of wire,

                      ∴ Area = π r²

Area of wire  = 3.14 × 0.5 × 10⁻³ × 0.5 × 10⁻³ m²

                      = 0.785 × 10⁻⁶ m²

It is given that, Length of conducting wire is 0.5 Ωm

Now, putting the values in the formula of resistivity:

Resistivity = Resistance  ×  Area  / Length

                    ρ = R × A / L

ρ = 30 ×  0.785 × 10⁻⁶ / 0.5 Ω m

ρ  = 47.1  × 10⁻⁶  Ω m

ρ  = 4.71  × 10⁻⁵  Ω m

Therefore, resistivity of wire is 4.71 × 10⁻⁵ Ω m.