The length of a diagonal of a cubiod is 5root5 and the sum of its length ,breadth and heigth is 19 cm .find its surface area
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The length of a diagonal of a cubiod = 5√5 =√(l² + b² + h²)
the sum of length ,breadth and heigth of the cuboid = 19cm = l+b+h
surface area of a cuboid = 2(lb+bh+lh)
(l+b+h)² = l² + b² + h² + 2lb+2bh+2lh
19² = (5√5)² + 2(lb+bh+lh)
361 = 125 + 2(lb+bh+lh)
2(lb+bh+lh) = 236cm
therefore surface area of the cuboid is 236cm
the sum of length ,breadth and heigth of the cuboid = 19cm = l+b+h
surface area of a cuboid = 2(lb+bh+lh)
(l+b+h)² = l² + b² + h² + 2lb+2bh+2lh
19² = (5√5)² + 2(lb+bh+lh)
361 = 125 + 2(lb+bh+lh)
2(lb+bh+lh) = 236cm
therefore surface area of the cuboid is 236cm
ysnavneeth16:
Thanks a lot
Why have you taken l square +bsquare +hsquare tell me afst
Tell me fast
bcuz (a+b+c)^2= a^2 +b^2+c^2+2ab+2bc+2ac
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