the length of a floor 3m 30cm and the breadth 4m 40cm. what is the maximum length of square tiles that can completely cover the floor.
Answers
Answered by
38
Given:
Length of the floor
= 3m 30 cm = 330 cm
Breadth of the floor
= 4m40 cm = 440 cm
330 = 2×3×5×11
440 = 2×2 ×5×11
Their GCD is 2×5×11 = 110
Maximum length of the square tile
= The greatest number which divides both length and breadth
= GCD of 330 and 440
= 110 cm
I hope this answer helps you
Length of the floor
= 3m 30 cm = 330 cm
Breadth of the floor
= 4m40 cm = 440 cm
330 = 2×3×5×11
440 = 2×2 ×5×11
Their GCD is 2×5×11 = 110
Maximum length of the square tile
= The greatest number which divides both length and breadth
= GCD of 330 and 440
= 110 cm
I hope this answer helps you
Answered by
22
Length of floor = 3m 30cm = 3m + 30cm
= 300 cm + 30 cm
= 330 cm
Breadth of foor = 4m4cm = 4m + 40 cm
= 400 cm + 40 cm
= 440 cm
Largest length of square tiles = HCF of length and breath of floor
= HCF of {330 cm , 440cm}
= Common factor of 330cm and 440 cm
= 110 cm
Hence, largest length of square tiles is 110cm
= 300 cm + 30 cm
= 330 cm
Breadth of foor = 4m4cm = 4m + 40 cm
= 400 cm + 40 cm
= 440 cm
Largest length of square tiles = HCF of length and breath of floor
= HCF of {330 cm , 440cm}
= Common factor of 330cm and 440 cm
= 110 cm
Hence, largest length of square tiles is 110cm
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