Question

the length of a floor is 6 m 66cm and the breadth is 4 m 40 cm what is the maximum length of square tiles that can complete cover the floor se​

Answer 1

Answer:

Length of the floor =8 m 96 cm=896 cm

Breadth of the floor =6 m 72 cm=672 cm

H.C.F. of 896 and 672 is =2×2×2×2×2×7=224

So, the required size of the square tile must be 224×224

Hence, the minimum number of square tiles of the same size needed to cover the floor =

Area of one square tile

Area of the floor

=

(224×224)

(896×672)

=

50176

602112

=12

Hence, 12 square tiles each of 224 cm×224 cm will be needed to cover the entire floor.

Answer 2

Step-by-step explanation:

$Length \: of \: the \: floor =8 m 96 cm=896 cm \\ </p><p></p><p>Breadth \: of \: the \: floor= \\ 6 m 72 cm=672 cm \\ </p><p></p><p></p><p>H.C.F. of  \: 896 and 672  \: is \\  =2×2×2×2×2×7=224 \\ </p><p></p><p>So, the \: required \: size \: of \: the \\ \: square \: tile \: must \: be 224×224 \\ </p><p></p><p>Hence, the \: minimum \: number \: of \\ \: square \: tiles \: of \: the \: same \: size \\ \: needed \: to \: cover \: the \: floor \\  =\frac{Area \:  of  \: one \:  square  \: tile }{Area  \: of the floor  </p><p>} \\ </p><p></p><p>=\frac{(224×224) }{(896×672)} \\ </p><p></p><p>= \frac{60211}{50176} \\ </p><p></p><p>=12  \\ </p><p></p><p>Hence, 12  \: square \: tiles \: each \: of  \: \\ 224 cm×224 cm will \: be \: needed \: \\ to \: cover \: the \: entire \: floor.</p><p></p><p>$