the length of a hall is 18 m and the width 12 m. the sum of the areas of the floor and the flat roof is equal to the sum of areas of four walls. find the height of the wall.
Answers
Answered by
56
Length of hall = 18 m
Width of hall = 12 m
Area of floor + Area of celling = LSA
=> L ×B + L ×B = 2(L+B) H
=> 2 LB = 2(L+B) × H
=> 2 × 12 × 18 = 2 (18 + 12) H
=> H = 24×18 / 2 × 30
=> H = 4 × 18 / 10
=> H = 72 /10
=> Height of wall = 7.2 m
Width of hall = 12 m
Area of floor + Area of celling = LSA
=> L ×B + L ×B = 2(L+B) H
=> 2 LB = 2(L+B) × H
=> 2 × 12 × 18 = 2 (18 + 12) H
=> H = 24×18 / 2 × 30
=> H = 4 × 18 / 10
=> H = 72 /10
=> Height of wall = 7.2 m
sagar352:
you are great
Answered by
14
l = 20 cm
b = 16cm
----
=> 2(lb) = 2(l + b)h
=> 2(20)(16)) = 2(20 + 16)h
=> 640 = 72h
=> 72h = 640
=> h = 640/72
=> h = 8.89
b = 16cm
----
=> 2(lb) = 2(l + b)h
=> 2(20)(16)) = 2(20 + 16)h
=> 640 = 72h
=> 72h = 640
=> h = 640/72
=> h = 8.89
this is wrong
Similar questions