Question

the length of a hall is 20 metre and breadth 6 metre how many types of length 15 cm and breadth 8 cm will be required to fix on its floor​

Answer 1

Answer:

${\boxed{\bold{Tiles\:required=10000}}}$

Step-by-step explanation:

$\bf{Given}\begin{cases}\sf{Length\:of\:hall=20\:m}\\\sf{Breadth\:of\:hall=6\:m}\\\sf{Length\:of\:tiles=15\:cm}\\\sf{Breadth\:of\:tiles=8\:cm}\\\sf{Tiles\:required=?}\end{cases}$

${\boxed{\bold\purple{Area\:= Length \times Breadth}}}$

$\tt Now,Area\:of\:hall = (20\times 6)\:{m}^{2} \\\\\rightarrow{\boxed{\tt {Area\:of\:hall = 120\:{m}^{2}}}}$

____________________________

$\tt Now,length\:of\:tiles = \dfrac{15}{100}\:m \\\therefore\tt Length\:of\:tiles = 0.15\:m \\\\\therefore\tt Breadth\:of\:tiles=\dfrac{8}{100}\:m \\\therefore\tt Breadth\:of\:tiles = 0.08\:m$

_____________________________

$\tt Area\:of\:tiles = Length\times Breadth \\\rightarrow\tt Area\:of\:tiles=(0.15\times 0.08)\:{m}^{2} \\\therefore\tt Area\:of\:tiles = 0.012\:{m}^{2}$

_____________________________

$\tt Tiles\:required=\dfrac{Area\:of\:hall}{Area\:of\:tiles} \\\rightarrow\tt Tiles\:required=\dfrac{120}{0.012} \\\\\therefore{\boxed{\tt {Tiles\:required=10000}}}$

Answer 2

Answer:

10000 Tiles are required

Step-by-step explanation:

Correct Question :-

The length of a hall is 20 meter and breadth 6 meter how many tiles of length 15 cm and breadth 8 cm will be required to fix on its floor​

We Have :-

Hall of

Length = 20 m

Breadth = 6 m

Tiles of

Length = 15 cm

Breadth = 8 cm

To Find :-

Number of tiles required

Formula Used :-

Area of Rectangle = Length * Breadth

Solution :-

Hall :-

Length = 20 m = 20 * 100 cm = 2000 cm

Breadth = 6 m = 6 * 100 cm = 600 cm

Area of Hall

2000 * 600

1200000 cm²

Area of Tile

15 * 8

120 cm²

Tiles required = 1200000 / 120

                       = 10000

10000 Tiles are required