Question

the length of a LCD is 75 cm and breadth is 55 cm .Area of LCD is dash sq.cm .​

Answer 1

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$\huge{\bf{\green{\mathfrak{Question:-}}}}$

• The length of a LCD is 75 cm and breadth is 55 cm. Area of LCD is ____ cm² .

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$\huge {\bf{\orange{\mathfrak{Answer:-}}}}$

• $\textsf{Length of LCD = 75 cm.}$

• $\textsf{Breadth of LCD = 55 cm.}$

• $\textsf{Since, LCD (Display object/unit) is in the form of a Rectangle,}$

• $\boxed{\textsf{Area of LCD = Area of Rectangle}}$

• $\boxed{\sf Area \: of \: Rectangle \: =\: l * b \:units^{2}}$

• $\sf l * b \:units^{2}$

• $\sf 75 * 55$

• $\boxed{\sf 4,125 \:units^{2}.}$

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$\huge{\bf{\red{\mathfrak{Conclusion:-}}}}$

• $\boxed{\therefore{\sf Area\: of\: LCD\: =\: 4,125 \:units^{2}.}}$

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Answer 2

Given :-

Length = 2( Breadth)

If Length = L - 55 cm

Then Breadth = B +55 cm

And Area (A') = A + 75 cm²

Solution :-

Area of rectangle = Length × Breadth .

→ Initial Area :-

→ Area (A) = L × B

→ Area (A) = 2B × B .

→ Area (A) = 2B²

→ New Area .

→ Area (A') =( L-55 ) × (B +55)

→ Area (A') = (2B -55) × (B + 55)

→ Area (A') = 2B² + 110 B - 55B - 3025

→ Area (A') = 2B² + 55B - 3025

→ A' = A + 75 [ where A = 2B²]

→ 2B² + 75 = 2B² + 55B - 3025

→ 2B² - 2B² +75 + 3025 = 55B

→ 3100 = 55B

→ B = 3100/55

→ Breadth = 56.36 cm

→ length = 2(56.36)

→ Length = 112.72 cm

Hence the length of the given rectangle is 112.72 cm .