Question

The length of a line segment joining A(2,-3) and B is 10 units. If the the abscissa of B is 10 units then it ordinate can be

1 point

3 and -9

-3 and 9

6&27

-6 and -27

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Answer 1

answer is in the attachment

hope it's helpful

Answer 2

The length of a line segment joining A(2, -3) and B is 10 units. the abscissa of point B is 10 units.

To find : The ordinate of point B.

solution : let ordinate of point B is y.

then, point B = (10, y)

here distance between point A (2, -3) and point B(10, y) is 10 units.

using distance formula,

d = √{(x₁ - x₂)² + (y₁ - y₂)²}

⇒10 = √{(10 - 2)² + (y + 3)²}

⇒10 = √{8² + (y + 3)²}

squaring both sides and we get,

⇒10² = 8² + (y + 3)²

⇒100 - 64 = (y + 3)²

⇒(6)² = (y + 3)²

⇒y + 3 = ± 6

⇒y = -3 ± 6

⇒y = -9 and 3

Therefore ordinate can be -9 and 3