Question

The length of a metal is $l_{1}$ when the tension in it is $T_{1}$ and is $l_{2}$ when the tension is $T_{2}$. The original length of the wire is(a) $\frac{l_{1}+l_{2}}{2}$(b) $\frac{l_{1}T_{2}+l_{2}T_{1}}{T_{1}+T_{2}}$(c) $\frac{l_{1}T_{2}-l_{2}T_{1}}{T_{2}-T_{1}}$(d) $\sqrt{T_{1}T_{2}l_{1}l_{2}}$

Answer 1

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