the length of a metalic pipe is 70 cm, inner diameter is 10 cm and thickness is 5 mm. if desity of metal used is 8 g/cm^3, find mass of the pipe.
Answers
Answer:
9240 grams.
Step-by-step explanation:
In order to find the mass, we must find volume and then substitute it's value in the equation
Density = mass / Volume.
First, let''s find the Outer diameter of cylinder = 10 + 2(0.5) = 11 cm
Volume of pipe = Outer - inner volume.
= π.R².h - π.r².h(Where R is outer radius, r is inner radius and h is the height)
= π.h(R² - r²)
= 22/7 * 70 *(5.5² - 5²)
= 220 *(30.25 - 25)
= 220 * 5.25 = 1155 cm³
Now put it in the previous equation : Density = mass/ volume
=> Mass = Volume * Density
= 1155 * 8 = 9240 gm
Answer:
9240 g or 9.24 kg
Step-by-step explanation:
Given data:
Length of pipe (L)= 70 cm
Inner diameter (d) = 10 cm
⇒inner radius (r) = 5 cm
thickness (t) = 5 mm = 0.5 cm
Density (ρ) = 8 g/cm³
We can calculate outer radius as R = inner radius + thickness
= 5 cm + 0.5 cm
= 5.5 cm
By the definition of density, it is mass per unit volume. Mathematically:
ρ = mass/volume
Volume of cylindrical pipe = Area of rim x length (Please refer the attachment to understand area or rim)
Area of rim =Area of outer circle - Area of inner circle = π (R² - r²)
Hence, Volume = π (R² - r²) x L
= (22/7) (5.5² - 5²) x 70 cm³
= 1155 cm³
Substituting this value in the formula of density
ρ = mass of pipe / volume
8 g/cm³ = mass of pipe / 1155 cm³
mass of pipe = 8 g/cm³ x 1155 cm³
= 9240 g
