Question

The length of a minute hand of a wall clock is 8.4 cm, then the area swept by it in 15 minutes is

Answer 1

let the r of circle be the length of minute hand of a clock.

then the area of circle is

$\pi{r}^{2}$

it is given in the question that it covers 15 min

then the area req will equal to the 1/4 of area of cirle

$\pi {r}^{2} \div 4$

$\frac{22}{7} \times {8.4}^{2} \times \frac{1}{4}$

$3.14 \times 8.4 \times .3$

$55.44 {cm}^{2}$

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Answer 2

Answer:55.44

Step-by-step explanation:

Let r be 8.4 cm

15 minutes in a clock means 1/4 th of a circle

That is 360/4 degrees equals to the angle theta formed in 15 minutes by the minute hand of the clock.

This implies theta is 90° .

Area of a sector of a circle is

(Theta/360°) * πr^2

That is (90/360°) * (22/7) * (8.4)^2.

Upon calculation you get 55.44cm^2.

Hope it helps....

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