the length of a rectangle ABCD is 8 metre and its diagonal BP measures 10 cm find its breadth BC
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my answer to this question is 6
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Step-by-step explanation:
In ∆ABD,
applying Pythagoras theorem ,
AD^2 + AB^2 = DB^2. .......(1)
given,
AB = 8 cm,
DB = 10 cm.
from equation 1,
AD^2 = DB^2 - AB^2
AD^2 = 100 - 64
AD^2 = 36.
therefore,
AD = BC =6 cm. ............(in a rectangle opp sides are equal)
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