Question

the length of a rectangle exceeds its breadth by 17 meters if the perimeter is 178m find perimeter​

Answer 1

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ɢɪᴠᴇɴ :-

ᴘᴇʀɪᴍᴇᴛᴇʀ =178ᴍ

ʟᴇɴɢᴛʜ ɪs 17ᴍ ᴍᴏʀᴇ ᴛʜᴀɴ ʙʀᴇᴀᴅᴛʜ.

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ᴛᴏ ғɪɴᴅ :-

ʟᴇɴɢᴛʜ ᴀɴᴅ ʙʀᴇᴀᴅᴛʜ ᴏғ ʀᴇᴄᴛᴀɴɢʟᴇ.

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sᴏʟᴜᴛɪᴏɴ :-

ʟᴇᴛ ᴛʜᴇ ʟᴇɴɢᴛʜ ʙᴇ x+17ᴍ

ʟᴇᴛ ᴛʜᴇ ʙʀᴇᴀᴅᴛʜ ʙᴇ x ᴍ

➡ᴘᴇʀɪᴍᴇᴛᴇʀ ᴏғ ʀᴇᴄᴛᴀɴɢʟᴇ =2(ʟ + ʙ)

➡ 178=2(x+17+x)

➡178/2=2x+17

➡89-17=2x

➡72/2=x

➡36=x

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ʜᴇɴᴄᴇ :-

ᴛʜᴇ ʙʀᴇᴀᴅᴛʜ ɪs 36ᴍ.

ᴛʜᴇ ʟᴇɴɢᴛʜ ɪs 36+17=53ᴍ

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ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘs...... ✔✔

Answer 2

Answer:

Let's assume the breadth as x meters

So, the length as (x + 3) meters

According to Question,

Perimeter of Rectangular plot = 90m

2(length + breadth) = 90 m

✒ 2(x + 3 + x) = 90

✒2x + 3 = 90 / 2

✒ 2x + 3 = 45

✒ 2x = 45 - 3

✒ 2x = 42

✒ x = 42 / 2

✒ x = 21

$➱ \sf{Required \: Measurements -}$

• Breadth = x = 21 m

• Length = x + 3 = 21+ 3 = 24 m

• Hence, the length and breadth of the rectangular plot are 24 meters and 21 meters respectively