The length of a rectangle exceeds its breadth by 5cm if the length is decreased by 2cm and the breadth is increased by 5cm then the area of the new rectangle increased by 33cm square find the dimensions of the original rectangle
Answers
Answered by
1
Let
length=l
b=l-5
area=l^2-5l
New l=l-2
b=l-5+5=l
area =l×l-2=l^2-2l
ATQ
l^2-2l-l^2+5l=33
3l=33
l=11
b=6
length=l
b=l-5
area=l^2-5l
New l=l-2
b=l-5+5=l
area =l×l-2=l^2-2l
ATQ
l^2-2l-l^2+5l=33
3l=33
l=11
b=6
Answered by
0
Answer:
let
length=1
b=1-5
area= |^2-5|
new= 1=1-2
b=1-5+5=1
area=1*1-2=|^2-2|
ATQ
|^2-2|-|2-5|=33
31=33
1=11
b=6
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