Question

The length of a rectangle exceeds its breadth by 7 cm . if the length is decreased by 4 cm and breadth is increased by 3, the new rectangle is the same as the area of the original rectangle. Find the length and the breadth of the original rectangle

Answer 1

B =x
L= x+7

Original Area =x×(x×7)=x^2+7x

New length =x+7-4=x+3
New breadth =x+3

New area =(x+3)(x+3)=x^2+6x+9

A2Q

=x^2+7x =x^2+6x+9
=x^2- x^2+7x=6x+9
=7x-6x=9
=x=9cm=Breadth
9+7=16cm=Length

Answer 2

Answer:

let the Breadth=X cm

The length exceed 7cm=(X+7)cm

Breadth is exceed by 3=(X+3)cm

length is decreased by

4=(X+7-4)=X+3 cm

Area=length×Breadth

According To The Question

X(X+7)=(X+3)×(X+3)

x^2-7x=x^2+3x+3x+9

x^2+7x-x^2-3x-3x=9

7x-6x=9

X=9

Breadth=9cm

Length=9+7=16cm