The length of a rectangle exceeds its breadth by 9 cm. If length and breadth are each increased by 3 cm, the area of new rectangle will be 84bcm² more than that of the given rectangle. Find the length and breadth of the given rectangle
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Answer:
Let the breadth of the rectangle be x cm.
Then, the length of the rectangle is (x+9) cm.
So, area of rectangle = length x breadth =x(x+9)cm
2
Now, length of new rectangle =(x+9+3) cm =(x+12) cm and
breadth of new rectangle =(x+3) cm.
So, area of new rectangle = length × breadth =(x+12)(x+3)cm
2
According to the given condition,
(x+12)(x+3)=x(x+9)+84
⇒x
2
+12x+3x+36=x
2
+9x+84
⇒15x+36=9x+84
⇒15x−9x=84−36
⇒6x=48
⇒x=8
So, breadth of the rectangle is 8 cm and length
=8+9=17 cm.
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