Math, asked by Rajveer47781, 1 year ago

the length of a rectangle exceeds its breadth by 9cm .if length and breadth each is increased by 3cm , the area of the new rectangle is 64 square cm more than the given rectangle

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Answered by Shalmali040203
2

Answer:

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Step-by-step explanation:


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Answered by sanchez21
0
Case 1 Case 2
Let breath=[X] cm breath=[X+3]cm
Length=[X+9] cm length =[X+9+3]cm
Area 1 = L×B Area 2=(64 ×area 1)cm.Sq
={X×(X+9)]cm. Sq

According to question..(finding the value of X)

Area 2 = L×B
64 ×area 1= L×B
64×X×(X+9)=(X+3)×(X+9+3)
64×(X*X) +9X=(X*X)+12X+3X+36
64+9X=12X+3X+36
64-36=12X+3X-9X
28=15X-9X
28/6=X


therefore,
Original length =(X+9)cm
=(28/6×9)cm
=42cm
(as according to question length exceed breath by 9 cm) therefore,
Original breath =(42-9)cm
=33cm

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