the length of a rectangle exceeds its breath by 4cm if length and breath is each increased by 3cm ,the area of new rectangle will be 81cmsq more than the given rectangle .find the length and breath of the given rectangle
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let the breadth be x
so the length is x+4cm
area = x × (x+4) -(1)
ATQ if we increase length and breadth 3cm more the result will found is 81 square cm more
then the length= x+4+3 cm = x+7 cm
breadth= x+3 cm
area = (x+3)(x+7). -(2)
the difference between these areas are 81 cm square
= (x+3)(x+7) - x(x+4 ) = 81 square cm
x^2 + 7x + 3x +21 - [x^2 + 4x] = 81 cm square
= x^2 + 10x + 21 - x^2 -4x = 81 cm square
6x +21 = 81 cm square
6x = 81-21 = 60 cm Square
6x = 60 cm square
x = 60/6 = 10 cm
breadth = 10 cm
length = x+4 cm = 10 + 4 = 14 cm
hope this helps you
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let the breadth be x
so the length is x+4cm
area = x × (x+4) -(1)
ATQ if we increase length and breadth 3cm more the result will found is 81 square cm more
then the length= x+4+3 cm = x+7 cm
breadth= x+3 cm
area = (x+3)(x+7). -(2)
the difference between these areas are 81 cm square
= (x+3)(x+7) - x(x+4 ) = 81 square cm
x^2 + 7x + 3x +21 - [x^2 + 4x] = 81 cm square
= x^2 + 10x + 21 - x^2 -4x = 81 cm square
6x +21 = 81 cm square
6x = 81-21 = 60 cm Square
6x = 60 cm square
x = 60/6 = 10 cm
breadth = 10 cm
length = x+4 cm = 10 + 4 = 14 cm
hope this helps you
plz mark as brainliest answer plzzzzz plzzzzzzzzzzzzz mark as brainliest answer plzzzzz
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