Question

The length of a rectangle exceeds its width 8 cm the area of rectangle is 240 cm find the dimension of the rectangle

Answer 1

ANSWER :

Let the width be 'x'

Given that the length exceeds the width by 8 cm

The length of rectangle be ( x + 8 )

Also, given that area = 240 cm^2

Area of rectangle = l x b

=> 240 = ( x + 8 ) ( x )

=> 240 = x^2 + 8x

=> x^2 + 8x - 240 = 0

=> x^2 - 12x + 20x - 240 = 0

=> x ( x - 12 ) + 20 ( x - 12 ) = 0

=> ( x + 20 ) ( x - 12 ) = 0

Equate each term with zero to find the value of the variable

=> x + 20 = 0 or x - 12 = 0

=> x = - 20 or x = 12

As it is distance, the value cannot be negative. So, reject the negative value

=> Width = x = 12 cm

Length = x + 8 = 20 cm

Therefore, the length is 20 cm and the width is 12 cm

Hope this helps you☺☺