The length of a rectangle exceeds its width by 5 m. If the width is increase by 1 m and the length is decreased by 2m, the area of new rectangle is 4 sq.m less than the area of original rectangle. Find the dimensions of the original rectangle.
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Answer:
12 m
Step-by-step explanation:
The area is A = LW for a rectangle.
We have originally
L = W + 5
Then the area is (W+5)W = W^2 + 5W
Then
(L-2)(W+1) = W^2 + 5W - 4
Substituting we get
(W+5 - 2)(W+1) = W^2 + 5W - 4
(W + 3)(W + 1) = W^2 + 5W - 4
W^2 + 4W + 3 = W^2 + 5W - 4
and W = 7 m so that
L = 12 m
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