Question

The length of a rectangle exceeds its width by 7m. If the width is decreased by 3m and the length decre
by 10m, the area is decreased by 95 sq. metres. Find the dimensions of the rectangle.​

Answer 1

Answer:

Step-by-step explanation:

Let width= x

Length of Original Rect.

= (x + 7)m

Original area = x × (x + 7)

New width = (x - 3)m

New length = (x + 7) - 10 = (x - 3)m

New area = (x-3)(x-3) = (x-3)^2

Original area - new area = 95 sq.m

x(x+7) - (x-3)^2 = 95

x^2 + 7x - x^2 - 9 + 6x = 95

13x = 104 => x = 8

Dimensions of rectangle

Width = 8m,

length = x + 7 = 8 + 7 = 15m

Answer 2

Answer:

length=13.8,breadth=6.8

Step-by-step explanation:

let the width of rect=b

the length of rect=b+7

if the width is decreased by 3m the new width =b-3

length=b-7

area=ar-95

(b)×(b+7)=area

b2+7b=area

new area =b2+7b-95

(b-3)×(b-7)=b2+7b-95

116=17b

b=116/17

b=6.8

l=13.8