Question

The length of a rectangle exceeds its width by2m
If its perimeter is 20 m, find its dimensions.
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Answer 1

$\bf\huge\underline{Answer}$

The dimensions of the rectangle are 6 m and 4 m respectively.

Explanation :-

Given :

• The length of a rectangle exceeds it's width by 2 m
• Perimeter of the rectangle is 20 m.

To find :

The dimensions of the rectangle

Solution :

Let the width of the rectangle be x m

and the length be (x + 2) m

We know that,

Perimeter of rectangle = 2 (l + b)

=> Perimeter = 20 m

=> 2{x + (x + 2)} = 20

=> 2 { x + x + 2 } = 20

=> 2 { 2x + 2 } = 20

=> 4x + 4 = 20

=> 4x = 20 - 4

=> 4x = 16

=> x = 16/4

=> x = 4

Therefore,

The width of the rectangle => x = 4 m

The length of the rectangle => (x + 2) = (4 + 2) = 6 m

Answer 2

SOLUTION :

Let the width of the rectangle be x

Length of rectangle = x + 2

The perimeter of rectangle = 20m

We know that,

Perimeter of rectangle = 2 [ l + b ]

According to the problem,

20 = 2 [ x + x + 2 ]

20 = 2 [ 2x + 2 ]

20 = 4x + 4

20 - 4 = 4x

=> 4x = 16

=> x= 16/4

=> x = 4

Width of rectangle = x = 4

Length of rectangle = x + 2 = 6

Therefore, the length and breadth of the rectangle are 6m and 4m respectively.