Question

The length of a rectangle exceeds its width by2m. If its perimeter is 20 m, find its dimensions.​

Answer 1

Answer:

breadth - x

length - x + 2

perimeter - 2(l+b)

20 = 2 ( x + x + 2 )

10 = 2x + 2

2x = 8

x = 8/2

x = 4 (breadth)

x + 2 = 6 (length)

........

Step-by-step explanation:

Answer 2

Answer:

• The dimensions of the rectangle are 6 m and 4 m respectively.

Given:

• The length of a rectangle exceeds its width by 2m and the perimeter of the rectangle is 20 m.

Need to find:

• The dimensions of the rectangle = ?

Solution:

Let,

• The width of the rectangle = y

Then,

• The length of the rectangle = y + 2

Formula used here:

• Perimeter = 2 × (length + breadth)

Putting the values:

➜ 20 = 2 × [y + (y + 2)]

➜ 20 = 2 × (2y + 2)

➜ 20 = 4y + 4

➜ 20 - 4 = 4y

➜ 4y = 16

➜ y = 16/4

➜ y = 4

Now,

• The width of the rectangle (y) is 4.
• The length of the rectangle(y+2) is 6.

Therefore:

• The dimensions of the rectangle are 6 m and 4 m respectively.

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬