Question

the length of a rectangle exceeds the breadth by 3 m and perimeter is 5 times the breadth find the Length breadth and the perimeter of the rectangle​

Answer 1

Let the breadth be x. So length will be (x+3) and perimeter will 5x

perimeter of rectangle=2(L+B)

5x=2[(x+3)+x]

5x=2(x+3)+2x

5x=2x+6+2x

5x-4x=6

x=6. (breadth)

(x+3)=(6+3)=9. (length)

perimeter=2(9+6)
=30m

hope it will help you

Answer 2

Let the breadth be 'x' metres.

Then the length would be 3 metres more than the breadth=(X+3) metres

Now, the perimeter is 5 times the breadth=5x metres

ATQ:-

=>2×(Length+Breadth)=Perimeter

=>2×(x+X+3)=5x

=>2×(2x+3)=5x

=>4x+6=5x

=>6=5x-4x

=>6=X

So, the breadth

=X m

=6 m

Length

=(X+3) m

=(6+3) m

=9 m

Perimeter

=2×(Length+Breadth)

=2(6+9)=2×15=30 m