The length of a rectangle exceeds the width by 2cm. If the diagonal is 10cm² find the width of this rectangle.{show your working}
Answers
Answered by
9
Answer:
follow me
Step-by-step explanation:
the length of a rectangle exceeds the width by 2 cm. If the diagonal is 10 cm long, find the width of the rectangle.
.
Let w = width
then
w+2 = length
.
applying Pythagorean theorem we have:
w^2 + (w+2)^2 = 10^2
w^2 + (w+2)(w+2) = 100
w^2 + (w^2+4w+4) = 100
2w^2+4w+4 = 100
w^2+2w+2 = 50
w^2+2w-48 = 0
(w+8)(w-6) = 0
w = {-8, 6}
throw out the negative solution leaving:
w = 6 cm
Similar questions