Question

The length of a rectangle field is 8 meters less than twice its breadth if the perimeter of the rectangle field is 56 meters find the length and breadth​

Answer 1

let the breadth of rectangle(b) = x m

then length(l) = (2x-8) m

A/q,

     perimeter of rectangle = 56 m

⇒  2(l+b) = 56

⇒  2(2x-8+x) = 56

⇒    3x-8 = 28

⇒     3x =28+8

⇒     x = 36/3 = 12 m

therefore length(l) = 2x-8 =2×12 - 8 =16 meters

              breadth(b) = x = 12 meters